Customize cell(s) appearance with CSS according to an expression in the data used in the grid.
Usage
grid_style_cell(
grid,
expr,
column,
background = NULL,
color = NULL,
fontWeight = NULL,
...,
class = NULL,
cssProperties = NULL
)
grid_style_cells(
grid,
fun,
columns,
background = NULL,
color = NULL,
...,
class = NULL,
cssProperties = NULL
)
Arguments
- grid
A grid created with
datagrid()
.- expr
An expression giving position of row. Must return a logical vector.
- column
Name of column (variable name) where to apply style.
- background
Background color.
- color
Text color.
- fontWeight
Font weight, you can use
"bold"
for example.- ...
Other CSS properties.
- class
CSS class to apply to the row.
- cssProperties
Alternative to specify CSS properties with a named list.
- fun
Function to apply to
columns
to identify rows to style.- columns
Columns names to use with
fun
.
Examples
library(toastui)
datagrid(mtcars) %>%
grid_style_cell(
mpg > 19,
column = "mpg",
background = "#F781BE",
fontWeight = "bold"
)
datagrid(mtcars) %>%
grid_style_cell(
vs == 0,
column = "vs",
background = "#E41A1C80",
color = "#FFF"
) %>%
grid_style_cell(
vs == 1,
column = "vs",
background = "#377EB880"
)
# Use rlang to use character
library(rlang)
my_var <- "disp"
datagrid(mtcars) %>%
grid_style_cell(
!!sym(my_var) > 180,
column = "disp",
background = "#F781BE"
)
# Style multiple columns
cor_longley <- as.data.frame(cor(longley))
cor_longley$Var <- row.names(cor_longley)
vars <- c("GNP.deflator", "GNP",
"Unemployed", "Armed.Forces",
"Population", "Year", "Employed")
datagrid(cor_longley[, c("Var", vars)]) %>%
grid_style_cells(
fun = ~ . > 0.9,
columns = vars,
background = "#053061",
color = "#FFF"
) %>%
grid_style_cells(
fun = ~ . > 0 & . <= 0.9,
columns = vars,
background = "#539dc8",
color = "#FFF"
) %>%
grid_style_cells(
fun = ~ . < 0,
columns = vars,
background = "#b51f2e",
color = "#FFF"
)